Summit - An Interactive Algebra Journey/Summit, An Interactive Algebra Journey.iso/SUMMIT/UTILS/C1/S4/P5

Text File | 1996-07-10 | 3KB | 42 lines

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1(-20,20) $42(No, that's incorrect. Try again.HINT: )$43($4255Since 1 is negative, the absolute value is the additive inverse of 1.)$44($4255Since 1 is positive, the absolute value is the number itself.)$45($4255)$46($4255The absolute value of a number is the number or its opposite, whichever is not negative.)
2(1p)
Use absolute value to simplify.∞1∞ =  ? iT11Use absolute value to simplify.∞1∞ =  ? Since 1 is #if(1>0)not #endifnegative, its absolutevalue is #if(1>0)itself#else-(1)#endif.pThen,5∞1∞ = #if(1<0)-(1) = #endifc22c0.
2#if(1<0)#1@$43#else#-1@$44#endif_$46
1(-15,-2) $42(No, that's incorrect. Try again.HINT: )$43($4255Take absolute value first. Then take the additive inverse of the absolute value.)$46($4255Find the additive inverse of the absolute value of 1. Check your sign.)
2(1i)
Use absolute value to simplify.-∞1∞ =  ? iT11Use absolute value to simplify.-∞1∞ =  ? You should read this as, "the additive inverse of the absolute value of negative 2."pAlways take the absolute value of a number first andthen apply any sign that is outside.Since ∞1∞ is 2, this becomes "the additive inverseof 2."pWe find the additive inverse of a number by changingits sign.p-∞1∞ = c21c0.
1#2@$43_$46
1,2(-9,9)$1((2))$3(2) $42(No, that's incorrect. Try again.HINT: )$43($4255The sum is positive. The absolute value of a positive number is that number.)$44($4255Add inside the absolute value bars before taking absolute value.)$46($4255Perform operations inside absolute value bars first before taking absolute value. Check signs.) n(1=2)
3(1e2+)4(3p)12(2e2p/2+)14(4i)15(1p2p+)20(1)
Use absolute value to simplify.∞1 + $12∞ =  ? iT11∞1 + $12∞ =  ? First, perform the operations inside theabsolute value symbols.5= ∞3∞pThen find the absolute value.5= c24c0
4#if(1>0&2>0)#14@$43#endif #if(1e2*<0)#15@$44#endif#_$46
2(-9,-1)1(-15,-1)n(1ei<2ei)n(1=2)
3(1ei)4(2ei)5(4e3-2/3+)n(5e2m>0)
Choose the correct symbol, < or >, between these two numbers.∞2∞  ?  ∞1∞iT12∞2∞  ?  ∞1∞"G\NUM3.35.2         4      5:2       3After simplifying, we locate the numbers on the number line and we see that 4, which is ∞2∞, is to the left of 3, which is ∞1∞. Thus, 4 is less than 3.p∞2∞ c2<c0 ∞1∞p
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2,1(-9,-1)n(1<2)n(1=2)
5(2e1-2/1+)n(5ei2m>0)
Choose the correct symbol, < or >, between these two numbers.-∞2∞  ?  -∞1∞iT12-∞2∞  ?  -∞1∞:G\NUM3.35.2        2      5      1After simplifying, we locate the numbers on the number line and we see that 2, which is -∞2∞, is to the left of 1, which is -∞1∞. Thus, 2 is less than 1.p-∞2∞ c2<c0 -∞1∞p
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